The example on rCCA does not show how to compute correlation significance. Can this function be used to do that?
Thanks!
The example on rCCA does not show how to compute correlation significance. Can this function be used to do that?
Thanks!
The answer is no, you could extract the components (canonical variates) from the rcc result and use the base stat function cor.test().
Thanks! is the No
because of the regularization?
If so, if I don’t apply regularization because of n > p + q
, i.e. setting lambda 1 and 2
as 0, should the function be the right one?
hi @blueskypie
Apologies for the delay in my answer. I had not seen the link of the function in your earlier message! (hence the ‘no, rcca cannot do this’). I looked at the p.asym()
function. The theoretical setting seems to be for N >> P+Q (cancor()
function for the CCA) so I am not sure it would work for rCCA. Since you do not need much regularisation, I would suspect the two results would look similar (CCA vs rCCA + p.asym()
).
Kim-Anh